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Home/ Questions/Q 538967
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:05:13+00:00 2026-05-13T10:05:13+00:00

Please help me out guys. I’m just trying to declare a simple result tree

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Please help me out guys. I’m just trying to declare a simple result tree fragment and iterate over it.


…

<xsl:variable name="rtf">
  <item-list>
    <item id="1">one</item>
    <item id="2">two</item>
    <item id="3">three</item>
    <item id="4">four</item>
  </item-list>
</xsl:variable>

<xsl:for-each select="msxsl:node-set($rtf)/item-list/item">
  <xsl:value-of select="@id"/>
</xsl:for-each>

…


Am I completely mistaken about how this works?


Edit:
I’m using .NET XslCompiledTransform and have the correct msxsl namespace declarations – xmlns:msxsl=”urn:schemas-microsoft-com:xslt”

The transformating executes fine – the problem is that nothing is output

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  1. Editorial Team
    Editorial Team
    2026-05-13T10:05:14+00:00Added an answer on May 13, 2026 at 10:05 am

    My suspicion is that you have a default namespace declared in your stylesheet. That would effectively place the <item-list> and <item> elements into a namespace. To select namespace-qualified elements using XPath 1.0, you must always use a prefix in the expression.

    So if you have something like this at the top of your stylesheet:

    <xsl:stylesheet xmlns="http://example.com"...>
    

    Then you’ll need to also add this:

    <xsl:stylesheet xmlns="http://example.com" xmlns:x="http://example.com"...>
    

    And then use the “x” prefix in your XPath expression:

    <xsl:for-each select="msxsl:node-set($rtf)/x:item-list/x:item">
      <xsl:value-of select="@id"/>
    </xsl:for-each>
    

    Let me know if that did the trick. I’m only speculating here.

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