Question

Please help me to form the SQL query…
I have a table in DB2 i.e. SVA1ARTICLE,

TABLE NAME:

SVA1ARTICLE

Table having the column

ID
KEYWORD1
KEYWORD2
KEYWORD3
KEYWORD4

Requirement:

1. Need to find out the KEYWORD which is at least repeated 100 times from all 4 individual KEYWORDS COLUMN i.e. also UNIQUE. for ex. budget is the keyword in COL KEYWORD1 and repeated 100 times then result will return budget. same applies with other KEYWORD field.

2. From result return from the above query we need to find out all the column from same table. i.e. if above query return ‘budget’ as keyword then, we need to find out all the record which having keyword budget and gives us the first 50 latest rows.

Please help your warrior who is the frontier with sword only no extra ammunition in hand.

Thanks,
Gladiator

Answer 1

I agree zxq9 post. You need to normalize your database. Middle time:

“Normalized” data:

create view SVA1ARTICLE_N
as
   select ID, keyword1 as k
   from SVA1ARTICLE union all
   select ID, keyword2 as k
   from SVA1ARTICLE union all
   select ID, keyword3 as k
   from SVA1ARTICLE union all
   select ID, keyword4 as k
   from SVA1ARTICLE 

“Find out the KEYWORD which is at least repeated 100 times from all 4
individual KEYWORDS COLUMN”

create view key_100
as
   select k
   from SVA1ARTICLE_N
   group by k
   having count(*) > 100

“From result return from the above query we need to find out all the
column from same table. i.e. if above query return ‘budget’ as keyword
then, we need to find out all the record which having keyword budget
and gives us the first 50 latest rows.”

select distinct id
from SVA1ARTICLE_N
where k in (select k from key_100)

This query returns ID for rows that match your criteria, be free to complete your self the query getting last 50 rows from SVA1ARTICLE source table.