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Home/ Questions/Q 598511
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T16:23:46+00:00 2026-05-13T16:23:46+00:00

Please help me undestand how order by influences to over clause. I have read

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Please help me undestand how order by influences to over clause. I have read msdn and one book and still misunderstood.

Let’s say we have such query:

SELECT Count(OrderID) over(Partition By Year(OrderDate))
      ,*
FROM [Northwind].[dbo].[Orders]
ORDER BY OrderDate

The result is that each raw has the column with the value how many entries in the table have the same year.

alt text http://img-fotki.yandex.ru/get/3912/svin80.2/0_3b871_3bb591da_XL

But what’s happened when i try this query?:

SELECT ROW_NUMBER() over(Partition By Year(OrderDate)
                         order by OrderDate) as RowN
      ,*
FROM [Northwind].[dbo].[Orders]
ORDER BY RowN

alt text http://img-fotki.yandex.ru/get/3908/svin80.2/0_3b872_c9352fb1_XL

Now I see the only thing that each RowN has 3 different years for each value (1996, 1997, 1998). I expected that RowN will be the same value for all 1996 year dates. Please explain me what happens and why.

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  1. Editorial Team
    Editorial Team
    2026-05-13T16:23:47+00:00Added an answer on May 13, 2026 at 4:23 pm

    In this case:

    SELECT ROW_NUMBER() over(Partition By Year(OrderDate)
     order by OrderDate) as RowN,*
      FROM [Northwind].[dbo].[Orders]
      order by RowN
    

    What you’re seeing it it’s giving you a row number that is partitioned by year, meaning that each year has it’s own climbing row number. To make this a bit cleaerer in the results:

    SELECT ROW_NUMBER() over(Partition By Year(OrderDate)
     order by OrderDate) as RowN,*
      FROM [Northwind].[dbo].[Orders]
      order by RowN, Year(OrderDate)
    

    This means that each year, say 1997, will have orders 1 through n ordered by the date that year…like this was the 1st order of 1997, 2nd order of 1997, etc.

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