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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T21:15:00+00:00 2026-05-14T21:15:00+00:00

please help me with a simple PHP doubt. I have a simple form: <

  • 0

please help me with a simple PHP doubt.

I have a simple form:

< form action=”foo” >
< label >Person:< /label >
< input type=”text” id=”name” >
< input type=”text” id=”last_name” >
< a href=”javascript:addmore();”>Add More

< /form >

Every time the user clicks Add More two new input fields will be dynamically created using jQuery. This can be done several times in a same form.

< form action=”foo” >
< label>Person:< /label >
< input type=”text” id=”name” >
< input type=”text” id=”last_name” >

< input type=”text” id=”name_2″ >
< input type=”text” id=”last_name_2″ >

< a href=”javascript:addmore();”>Add More
< input type=”sbumit” >
< /form >

Each pair (name and last_name) should create on record in my db.

Two Questions:
1) What is the best option for input id? Appending a counter is the best option?
2) How can I handle it in the backend using php?

Let me know if you need more info.

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-14T21:15:01+00:00Added an answer on May 14, 2026 at 9:15 pm

    Some code got lost in your post. And your form needs a method, probably POST.

    Still, the best option would be creating inputs with the same name ending with []:

    <input type="text" name="firstname[]" value="Fred" />
    <input type="text" name="firstname[]" value="John" />
    

    PHP will see it as an array with such elements:

    <?php
    $_POST['firstname'][0] // Fred
    $_POST['firstname'][1] // John
    ?>
    

    That is if you submit the form once for all the records. If you want to immediately save every record, google for ajax tutorials.

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