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Home/ Questions/Q 6978339
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Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T17:44:33+00:00 2026-05-27T17:44:33+00:00

Please help me with regular expression. I found this good peace of code: var

  • 0

Please help me with regular expression.

I found this good peace of code:

    var ify = function() {
      return {
        "link": function(t) {
          return t.replace(/(^|\s+)(https*\:\/\/\S+[^\.\s+])/g, function(m, m1, link) {
            return m1 + '<a href=' + link + '>' + ((link.length > 25) ? link.substr(0, 24) + '...' : link) + '</a>';
          });
        },
        "at": function(t) {
          return t.replace(/(^|\s+)\@([a-zA-Z0-9_]{1,15})/g, function(m, m1, m2) {
            return m1 + '@<a href="http://twitter.com/' + m2 + '">' + m2 + '</a>';
          });

    },
    "hash": function(t) {
      return t.replace(/(^|\s+)\#([a-zA-Z0-9_]+)/g, function(m, m1, m2) {
        return m

1 + '#<a href="http://search.twitter.com/search?q=%23' + m2 + '">' + m2 + '</a>';
          });
        },
        "clean": function(tweet) {
          return this.hash(this.at(this.link(tweet)));
        }
      };
    }();

But its not working properly.

At first in my page there can be <b>@username</b> and for this cause regex isnt working (i think I need to append this characters “<” and “>” to the “at function”. But how?)

At second in “hash” function in my page, in query there can be other non a-zA-Z characters). For example “такие символы” or “ñ” or others. And formatted string will look like #<a href="twitter.com/?q=Catalu">Catalu</a>ña for #Cataluña word

Please help me. Thank you!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T17:44:34+00:00Added an answer on May 27, 2026 at 5:44 pm
    function processTweetLinks(text) {
        var exp = /(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|])/i;
        text = text.replace(exp, "<a href='$1' target='_blank'>$1</a>");
        exp = /(^|\s)#(\w+)/g;
        text = text.replace(exp, "$1<a href='http://search.twitter.com/search?q=%23$2' target='_blank'>#$2</a>");
        exp = /(^|\s)@(\w+)/g;
        text = text.replace(exp, "$1<a href='http://www.twitter.com/$2' target='_blank'>@$2</a>");
        return text;
    }
    
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