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Home/ Questions/Q 568805
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T13:13:39+00:00 2026-05-13T13:13:39+00:00

Please, I’m trying to get some total value of user earned points in few

  • 0

Please,

I’m trying to get some total value of user earned points in few distinctive counts, but everything is from same table.

SQL:

SELECT o.author_id, SUM(o.vote_value) AS vote_value, n.best AS best_sum, 
                (SUM(o.vote_value) + (10 * n.best)) AS total
                FROM comments o
                LEFT JOIN (
                  SELECT COUNT(best) AS best, author_id
                  FROM comments
                  WHERE best = 1
                  GROUP BY author_id
                  ) n ON o.author_id = n.author_id
                GROUP BY o.author_id
                ORDER BY total DESC
                LIMIT 0, 4

Problem is if there is no BEST (default is 0, and best is 1) I’m getting nothing for “total” and “best_sum”. I need 0 if user doesn’t have “best” so that calculation can be performed right

Sorry, my bad english I think You will understood
Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-13T13:13:39+00:00Added an answer on May 13, 2026 at 1:13 pm

    I think your problem is that you are filtering out the rows where best is not 1, so they aren’t included in the group by. Try this:

    SELECT o.author_id, SUM(o.vote_value) AS vote_value, n.best AS best_sum, 
                (SUM(o.vote_value) + (10 * n.best)) AS total
                FROM comments o
                JOIN (
                  SELECT SUM(best) AS best, author_id
                  FROM comments
                  GROUP BY author_id
                  ) n ON o.author_id = n.author_id
                GROUP BY o.author_id
                ORDER BY total DESC
                LIMIT 0, 4
    

    Also, maybe I’m missing something but wouldn’t this work, saving the subquery?

    SELECT o.author_id, SUM(o.vote_value) AS vote_value, SUM(o.best) AS best_sum, 
                (SUM(o.vote_value) + (10 * SUM(o.best))) AS total
                FROM comments o
                GROUP BY o.author_id
                ORDER BY total DESC
                LIMIT 0, 4
    
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