Question

Please look at my code:

function getShopConfig()
{

$sql = "SELECT sc_name, sc_address, sc_phone, sc_email, sc_shipping_cost, sc_order_email, cy_symbol, sc_currency
        FROM kol_shop_config , kol_currency
        WHERE sc_currency = cy_id";
$result = dbQuery($sql);
$row    = dbFetchAssoc($result);

if ($row) {
    //extract($row);

 $shopConfig = array('name'           => $row['sc_name'],
                        'address'        => $row['sc_address'],
                        'phone'          => $row['sc_phone'],
                        'email'          => $row['sc_email'],
                        'sendOrderEmail' => $row['sc_order_email'],
                        'shippingCost'   => $row['sc_shipping_cost'],
                        'currency'       => $row['sc_currency']);
}
return $shopConfig;  

}

then im calling it like,

<td colspan="4" align="right"><?php getShopConfig(); echo $shopConfig['name'];?></td>

but nothing is being displayed.. where is the mistake?? please help.

note: both are in the same page. dbQuery() and dbFetchAssoc() functions are pre-defined and has worked properly before. if i echo it inside the function and then just call it then its working properly.

Answer 1

<?php
    $shopConfig = getShopConfig();
    echo $shopConfig['name'];
?>

You have to assign returned array to some ($shopConfig) variable before.