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Home/ Questions/Q 910399
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Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T17:02:15+00:00 2026-05-15T17:02:15+00:00

Please note that I want the compartment number to change. <?php $compartment = 1;

  • 0

Please note that I want the compartment number to change.

<?php
    $compartment = "1";

        /* HERE I NEED SOME SCRIPT TO FIND THE EXTENSION OF THE FILE NAME $compartment AND TO SAVE THAT AS A VARIABLE NAMED 'EXTENSION'.*/

    if (file_exists($compartment.$extension)) {
        echo "$compartment.$extension exists!
    } else {
        echo "No file name exists that is called $compartment. Regardless of extension."
    }
?>


<?php
    $compartment = "2";

        /* HERE I NEED SOME SCRIPT TO FIND THE EXTENSION OF THE FILE NAME $compartment AND TO SAVE THAT AS A VARIABLE NAMED 'EXTENSION'.*/

    if (file_exists($$compartment.$extension)) {
        echo "$compartment.$extension exists!
    } else {
        echo "No file name exists that is called $compartment. Regardless of extension."
    }
?>

Thank You!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T17:02:16+00:00Added an answer on May 15, 2026 at 5:02 pm

    You need glob().

    $compartment = "2";
    
    $files = glob("/path/to/files/$compartment.*"); // Will find 2.txt, 2.php, 2.gif
    
    // Process through each file in the list
    // and output its extension
    if (count($files) > 0)
    foreach ($files as $file)
     {
        $info = pathinfo($file);
        echo "File found: extension ".$info["extension"]."<br>";
     }
     else
      echo "No file name exists called $compartment. Regardless of extension."
    

    by the way, what you are doing above is crying for a loop. Don’ repeat your code blocks, but wrap one of them into this:

     $compartments = array(1, 3, 6, 9); // or whichever compartments 
                                        // you wish to run through
    
     foreach ($compartments as $compartment)
      {
       ..... insert code here .......
      }
    
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