Question

please refer to previous question here: Sum total for column in jQuery

i used Aymen’s solution, but i edited it to suite my need. It stopped working, my code as below as seen at jsfiddle: http://jsfiddle.net/unKDk/15/

<table id="sum_table" width="300" border="1">
    <tr class="titlerow">
        <td>Apple</td>
        <td>Orange</td>
        <td>Watermelon</td>
        <td>Strawberry</td>
        <td>Total By Row</td>
    </tr>
    <tr>
        <td class="rowAA">1</td>
        <td class="rowAA">2</td>
        <td class="rowBB">3</td>
        <td class="rowBB">4</td>
        <td class="totalRow"></td>
    </tr>
    <tr>
        <td class="rowAA">1</td>
        <td class="rowAA">2</td>
        <td class="rowBB">3</td>
        <td class="rowBB">4</td>
        <td class="totalRow"></td>
    </tr>
    <tr>
        <td class="rowAA">1</td>
        <td class="rowAA">5</td>
        <td class="rowBB">3</td>
        <td class="rowBB">4</td>
        <td class="totalRow"></td>
    </tr>
    <tr class="totalColumn">
        <td class="totalCol">Total:</td>
        <td class="totalCol">Total:</td>
        <td class="totalCol">Total:</td>
        <td class="totalCol">Total:</td>
        <td class="totalCol">Total:</td>
    </tr>
</table>

Jquery part is

var totals=[0,0,0,0,0];
$(document).ready(function(){

    var $dataRows=$("#sum_table tr:not('.totalColumn, .titlerow')");

    $dataRows.each(function() {
        $(this).find('.rowAA').each(function(i){        
            totals[i]+=parseInt( $(this).html());
        });

        $(this).find('.rowBB').each(function(i){        
            totals[i]+=parseInt( $(this).html());
        });        
    });
    $("#sum_table td.totalCol").each(function(i){  
        $(this).html("total:"+totals[i]);
    });

});

1. how to solve the problem that caused the jquery calculate wrongly.
2. how to calculate total by row
3. i need the class name exactly same.

Answer 1

I am not quite sure what you want, but if you just want to sum all rows by column then see below..

var totalsByRow = [0, 0, 0, 0, 0];
var totalsByCol = [0, 0, 0, 0, 0];
$(document).ready(function() {

    var $dataRows = $("#sum_table tr:not('.totalColumn, .titlerow')");

    $dataRows.each(function(i) {
        $(this).find('td:not(.totalRow)').each(function(j) {
            totalsByCol[j] += parseInt($(this).html());
            totalsByRow[i] += parseInt($(this).html());
        });
    });

    for (var i = 0; i < totalsByCol.length - 1; i++) {
        totalsByCol[totalsByCol.length - 1] += totalsByCol[i];       
    }    

    $("#sum_table td.totalCol").each(function(i) {
        $(this).html("total:" + totalsByCol[i]);
    });

    $("#sum_table td.totalRow").each(function(i) {
        $(this).html("total:" + totalsByRow[i]);
    });
});

DEMO