Question

Please see the example code below:

class A
{
private:
    class B
    {
    public:
        foobar();
    };
public:
    foo();
    bar();
};

Within class A & B implementation:

A::foo()
{
    //do something
}

A::bar()
{
    //some code
    foo();
    //more code
}

A::B::foobar()
{
    //some code
    foo(); //<<compiler doesn't like this
}

The compiler flags the call to foo() within the method foobar(). Earlier, I had foo() as private member function of class A but changed to public assuming that B’s function can’t see it. Of course, it didn’t help. I am trying to re-use the functionality provided by A’s method. Why doesn’t the compiler allow this function call? As I see it, they are part of same enclosing class (A). I thought the accessibility issue for nested class meebers for enclosing class in C++ standards was resolved.

How can I achieve what I am trying to do without re-writing the same method (foo()) for B, which keeping B nested within A?

I am using VC++ compiler ver-9 (Visual Studio 2008). Thank you for your help.

Answer 1

foo() is a non-static member function of A and you are trying to call it without an instance.
The nested class B is a seperate class that only has some access privileges and doesn’t have any special knowledge about existing instances of A.

If B needs access to an A you have to give it a reference to it, e.g.:

class A {
    class B {
        A& parent_;
    public:
        B(A& parent) : parent_(parent) {}
        void foobar() { parent_.foo(); }
    };
    B b_;
public:
    A() : b_(*this) {}
};