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Home/ Questions/Q 9120563
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T05:39:20+00:00 2026-06-17T05:39:20+00:00

Please see the example output at: connection refused The question I have is why

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Please see the example output at:
connection refused

The question I have is why the first call to s.connect() throws “Connection Refused”, but the second call throws “Invalid Argument”. It’s like the first call put the socket object s into some kind of error state. Is there a way to reset it?

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  1. Editorial Team
    Editorial Team
    2026-06-17T05:39:21+00:00Added an answer on June 17, 2026 at 5:39 am

    You are calling this:

    s.connect((gethostname(), 4444))
    

    gethostname() involves more than just connecting to server. It initializes the variables for the socket.

    Next time you call connect, s already have a value, but invalid. So, you get Invalid argument.

    Note: s.connect() actually calls connect() with s as the first argument, as connect is defines as def connect(self, ...).

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