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Home/ Questions/Q 7821399
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T07:38:18+00:00 2026-06-02T07:38:18+00:00

Please take a look at the code snippet below: interface IFoo<E>{ void doFoo(E env);

  • 0

Please take a look at the code snippet below:

interface IFoo<E>{
    void doFoo(E env);
}

class A<E>{
    public void doA(E env){}
}

public class Foo<E> implements IFoo<E>{
    public A<E> a;

    @Override
    public void doFoo(E env) {
        a.doA(env);
    }

    private class FooInner<E> implements IFoo<E>{

        @Override
        public void doFoo(E env) {
            a.doA(env);
        }
    }
}

Eclipse complains inside of private inner class a.doA(env) with the following message.

The method doA(E) in the type A<E> is not applicable for the arguments (E)

It doesn’t seem like accessibility issue because non-static inner class have an access to all instance variables of the outter class. It looks like I defined my generics wrong somewhere. Can anyone explain me what I am doing wrong here?

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  1. Editorial Team
    Editorial Team
    2026-06-02T07:38:22+00:00Added an answer on June 2, 2026 at 7:38 am

    The type of the enclosing class is part of the type of the inner class. FooInner is already parameterized by E, because it’s part of the outer class; the explicit parameterization is redundant and incorrect, because it’s actually trying to introduce a new type parameter using the same name as the existing one. Just remove the <E> in private class FooInner<E>, and you’re golden.

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