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Home/ Questions/Q 6924233
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:38:13+00:00 2026-05-27T10:38:13+00:00

Please tell me why iam always getting Server Upload Failed! in the code given

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Please tell me why iam always getting “Server Upload Failed!” in the code
given below.

int rval = 28;
char *return_str=NULL;

return_str = strdup((rval!=28) ? ("Server Upload Failed!") : ("Server TimeOut Reached!"));
printf(" return_str : %s\n", return_str);

Output that iam getting is ====> Server Upload Failed! . I want to know why it is not giving
"Server TimeOut Reached!" as output .

Platform : Linux , gcc-compiler

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:38:13+00:00Added an answer on May 27, 2026 at 10:38 am

    It looks correct to me, once I read it a couple of extra times. It should generate the latter string (“Server TimeOut Reached”).

    Not sure why you would ever need to call strdup() on a static string, instead of just using the literal directly. One case would be if there sometimes a need for a more dynamic string I guess, so whoever receives the value assumes it’s dynamic and takes ownership.

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