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Home/ Questions/Q 8652639
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T14:21:14+00:00 2026-06-12T14:21:14+00:00

Please tell me, why my simple application cannot mmap a small size of memory?

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Please tell me, why my simple application cannot mmap a small size of memory?

And, why such a specific boundary – 257UL?

// #define MAP_SIZE 256UL or below - fail
// #define MAP_SIZE 257UL - ok

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>
#include <errno.h>
#include <signal.h>
#include <fcntl.h>
#include <ctype.h>
#include <termios.h>
#include <sys/types.h>
#include <sys/mman.h>

#define FATAL do { fprintf(stderr, "Error at line %d, file %s (%d) [%s]\n", \
  __LINE__, __FILE__, errno, strerror(errno)); exit(1); } while(0)

#define MAP_SIZE 4096UL
#define MAP_MASK (MAP_SIZE - 1)

int main(int argc, char **argv) {
    int fd;
    void *map_base, *virt_addr;
    unsigned long read_result, writeval;
    off_t target = strtoul("0x00002000", 0, 0);

    if((fd = open("/dev/mem", O_RDWR | O_SYNC)) == -1) FATAL;
    printf("/dev/mem opened.\n");
    fflush(stdout);

    map_base = mmap(0, MAP_SIZE, PROT_READ | PROT_WRITE, MAP_SHARED, fd, target & ~MAP_MASK);
    if(map_base == (void *) -1) FATAL;
    printf("Memory mapped at address %p.\n", map_base);
    fflush(stdout);
...
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T14:21:15+00:00Added an answer on June 12, 2026 at 2:21 pm

    mmap works in multiples of the page size on your system. If you’re doing this on i386/amd64 or actually most modern CPUs, this will be 4096.

    In the man page of mmap on my system it says: “offset must be a multiple of the page size as returned by sysconf(_SC_PAGE_SIZE).”. On some systems for historical reasons the length argument may be not a multiple of page size, but mmap will round up to a full page in that case anyway.

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