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Home/ Questions/Q 6759407
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:56:08+00:00 2026-05-26T13:56:08+00:00

Plugin: http://plugins.jquery.com/project/socialbutton Implementation: http://alblaw.icvmgroup.net/index.cfm?pageid=12&itemid=835 I’m not new to JavaScript or jQuery by any means,

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Plugin: http://plugins.jquery.com/project/socialbutton

Implementation: http://alblaw.icvmgroup.net/index.cfm?pageid=12&itemid=835

I’m not new to JavaScript or jQuery by any means, but I’m at a loss with this implementation. I have the following, yet the plugin does not function and I get no errors:

<script type="text/javascript" src="scripts/socialbutton.js"></script>
<script type="text/javascript">
    $('.google_plusone').socialbutton('google_plusone');

    // Facebook / Like button
    $('.facebook_like').socialbutton('facebook_like');

    // Facebook / Share button
    $('.facebook_share').socialbutton('facebook_share');

    // Twitter / Tweet Button
    $('.twitter').socialbutton('twitter');

</script>
<div id="social-share">
    <div class="google_plusone"></div>
    <div class="facebook_like"></div>
    <div class="facebook_share"></div>
    <div class="twitter"></div>
</div>

What can I try next?

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:56:08+00:00Added an answer on May 26, 2026 at 1:56 pm

    Try putting your jQuery inside a $(document).ready(); function like this:

    $(document).ready(function() {
      $('.google_plusone').socialbutton('google_plusone');
    
      // Facebook / Like button
      $('.facebook_like').socialbutton('facebook_like');
    
      // Facebook / Share button
      $('.facebook_share').socialbutton('facebook_share');
    
      // Twitter / Tweet Button
      $('.twitter').socialbutton('twitter');
    });
    
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