Question

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Access random item in list

I have an array with numbers and I want to get random elements from this array. For example: {0,1,4,6,8,2}. I want to select 6 and put this number in another array, and the new array will have the value {6,….}.

I use random.next(0, array.length), but this gives a random number of the length and I need the random array numbers.

for (int i = 0; i < caminohormiga.Length; i++ )
{
    if (caminohormiga[i] == 0)
    {
        continue;
    }

    for (int j = 0; j < caminohormiga.Length; j++)
    {
        if (caminohormiga[j] == caminohormiga[i] && i != j)
        {
            caminohormiga[j] = 0;
        }
    }
}

for (int i = 0; i < caminohormiga.Length; i++)
{
   int start2 = random.Next(0, caminohormiga.Length);
   Console.Write(start2);
}

return caminohormiga;

Answer 1

I use the random.next(0, array.length), but this give random number of the length and i need the random array numbers.

Use the return value from random.next(0, array.length) as index to get value from the array

 Random random = new Random();
 int start2 = random.Next(0, caminohormiga.Length);
 Console.Write(caminohormiga[start2]);