Possible Duplicate: Android – How do I do a lazy load of images in

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Asked: June 4, 20262026-06-04T09:29:34+00:00 2026-06-04T09:29:34+00:00

Possible Duplicate: Android – How do I do a lazy load of images in

0

Possible Duplicate:
Android – How do I do a lazy load of images in ListView

Good day, I have done a listview with a text, image and a ratingbar. I get these information by using ksoap which i already done and it works like charm!

Now there is a problem, as i mentioned earlier, i do have a image inside the listview, if i didn’t remove the photo, it will become so laggy/slow response but after i remove the image, it will become smooth again just only with the textview and ratingbar.

How to solve the laggy if i wanted to include the images. please do tell me if u need a example so i will post the android .apk . I hope there is a solution for this.
below my code for the images at listview:

String s = strTitle[position];      
System.out.println(s);      
String image_URL = imageURL[position];      
BitmapFactory.Options bmOptions;
bmOptions = new BitmapFactory.Options();
bmOptions.inSampleSize = 1;
Bitmap bm = LoadImage(image_URL, bmOptions);
ivLogo.setImageBitmap(bm);              
return rowView;

private Bitmap LoadImage(String URL, BitmapFactory.Options options)
{
    Bitmap bitmap = null;
    InputStream in = null;       
    try {
        in = OpenHttpConnection(URL);
        bitmap = BitmapFactory.decodeStream(in, null, options);
        in.close();
    } catch (IOException e1) {  }
    return bitmap;               
}

private InputStream OpenHttpConnection(String strURL) throws IOException{
    InputStream inputStream = null;
    URL url = new URL(strURL);
    URLConnection conn = url.openConnection();

    try{
        HttpURLConnection httpConn = (HttpURLConnection)conn;
        httpConn.setRequestMethod("GET");
        httpConn.connect();

        if (httpConn.getResponseCode() == HttpURLConnection.HTTP_OK) 
        {
            inputStream = httpConn.getInputStream();
        }
    }
    catch (Exception ex){    }
    return inputStream;
}