Question

Possible Duplicate:
C programming, why does this large array declaration produce a segmentation fault?

I have written a simple program.

#include <iostream>

using namespace std;

int main(int argc, char* argv[])
{
    int genotype[150000000];
}

But I get a strange error:

RUN FAILED (exit value 1, total time: 131ms)

How can I save this amount of int?

(I have enough memory to save this amount of ints and my computer is 64-bit)

Answer 1

Your stack is too small. Put this on the heap, using new:

int* genotype = new int[150000000];

And i hope that following will be useful.

• signed char: -127 to 127 (note, not -128 to 127; this accommodates 1’s-complement platforms)
• unsigned char: 0 to 255
• “plain” char: -127 to 127 or 0 to 255 (depends on default char signedness)
• signed short: -32767 to 32767
• unsigned short: 0 to 65535
• signed int: -32767 to 32767
• unsigned int: 0 to 65535
• signed long: -2147483647 to 2147483647
• unsigned long: 0 to 4294967295
• signed long long: -9223372036854775807 to 9223372036854775807
• unsigned long long: 0 to 18446744073709551615

Or you can use limit.h to find out around what your program relies on.
For example, this is how you will find maximum range for int:

C:

#include <limits.h>
const int min_int = INT_MIN;
const int max_int = INT_MAX;

C++

#include <limits>
const int min_int = std::numeric_limits<int>::min();
const int max_int = std::numeric_limits<int>::max();