Question

Possible Duplicate:
Check whether a Directory Exists in PHP

I am trying scandir() to check contents of directories and sending path parameter using javascript and trying to load the contents in #container div:

$("#container").load("fetch_images.php?path="+pathvariable);

in fetch_images.php I am trying scandir($_GET['pathvariable']) to scan the elements of given directory. My problem is if proper path is not supplied using $_GET[‘pathvariable’] the page is showing some warning and error.

trying to scan like $files_dir_results = scandir($path); and using foreach() to display all results of the array.

I don’t want to show any kind of warning or error on output page. I know I can disable PHP warning but I will prefer any better option.

I don’t know how to check if scandir() is returing any error or warning. thanks.

Answer 1

You should first check if the path is valid with is_dir then scan it

$images = array();
$valid_images = array('jpg','png','gif');
if(is_dir($_GET['path'])){
  foreach(scandir($_GET['path']) as $file){
    $ext = pathinfo($file, PATHINFO_EXTENSION);
    if(in_array($ext, $valid_images)){
      array_push($images, $file);
    }   
 }
}

echo json_encode($images);