Question

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Convert a byte into a boolean array of length 4 in Java

I am currently studying java, and making games.
I have come on the situation with I need to make some test-data for a game.

I work with tiles in a 2D-array(a map of the game), and each tile needs four bool-values.
So instead of writing the tile in true or false, I want to use a simple Byte, written in binary.

Example: “0b0110” instead of “false, true, true, false”

So I need a way to convert my binary-written Bytes to arrays of Boolean.

Answer 1

You can do something like this:

byte b = 0b0110;
boolean [] flags = new boolean[4];
for (int i = 0; i < 4; ++i) {
    flags[i] = (b & (1 << i)) != 0;
}

Going the other way:

boolean [] flags = {false, true, true, false};
byte b = 0;
for (int i = 0; i < 4; ++i) {
    if (flags[i]) b |= (1 << i);
}

I would recommend using byte and boolean primitives unless you need to box them as Byte and Boolean for some other reason.