Question

Possible Duplicate:
Create instance of generic type in Java?

public class MyCache <T extends Taxable> {


    private Map<Long, T> map = new HashMap<Long, T>();

    public void putToMap(Long nip, T t){
        map.put(nip, t);
    }

    public T getFromMap(Long nip){
        return map.get(nip);
    }

}

public class TaxableFactory<T extends Taxable> {

    private MyCache<T> cache;

    public void setCache(MyCache<T> cache) {
        this.cache = cache;
    }

    public TaxableFactory() {

    }

    public void putT(T t) {
        cache.putToMap(t.getNip(), t);
    }

    public  T get(long nip) throws InstantiationException, IllegalAccessException {

        T myT = cache.getFromMap(nip);
        if (myT == null) {

            T newT ;
            putT(newT);

            return null;

        } else
            return myT;

    }

I tried many ways to create new T in my get method. Seems like I need little help 🙂 How to do it to m ake it work?

Answer 1

Even though you are using generics, you still would need to pass the Class as an argument if you want to obtain a new Instance of T.

public  T get(Class<T> clazz, long nip) throws InstantiationException, IllegalAccessException {

    T myT = cache.getFromMap(nip);
    if (myT == null) {

        T newT = clazz.newInstance();
        putT(newT);

        return newT;

    } else
        return myT;

}

You would then call it like this:

.get(SomeTaxable.class, someNip)