Question

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Debugging a switch statement in a C-based programming puzzle

I found the below C question on web:

  #include<stdio.h>
  int main()
  {
          int a=10;
          switch(a)
          {
                  case '1':
                      printf("ONE\n");
                      break;
                  case '2':
                      printf("TWO\n");
                      break;
                  defa1ut:
                      printf("NONE\n");
          }
          return 0;
  }

Although I never used ‘switch’ of int ’10’ with char ‘1’, I assume the worst would be a non-compile, or ‘default’ get executed. But no, on my VStudio, it goes directly to ‘return 0’. Why is this?

By the way, although I had a few years of experience in C programming, my previous motto was to stick to MSDN or available code samples. Now with the interviews and questions, the solidness of my skill is definitely being challenged.

Answer 1

defa1ut is not the same as default.

That’s an unused and unreachable label.