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Home/ Questions/Q 8779013
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T19:40:21+00:00 2026-06-13T19:40:21+00:00

Possible Duplicate: Declaring an array with a non-constant size variable This is my code:

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Possible Duplicate:
Declaring an array with a non-constant size variable

This is my code:

const int xsize=150;
char Hey[xsize];

I don’t understand why I cannot declare my new array Hey using the constant above.
Can anyone help in this?

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  1. Editorial Team
    Editorial Team
    2026-06-13T19:40:23+00:00Added an answer on June 13, 2026 at 7:40 pm

    It’s not valid C89 code. You can’t declare an array with variable size, even if the variable happens to be const.

    It would work if you had it as a #define rather than a const int. It is valid in C99, though. GCC and other compilers also offer it as an extension in C89 mode.

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