Question

Possible Duplicate:
Default value to a parameter while passing by reference in C++

Is it possible to do something like this:

// definition
bool MyFun(int nMyInt, char* szMyChar, double& nMyReferencedDouble = 0.0);

Then the function can be called either like this:

MyFun(nMyInt, szMyChar, nMyReferencedDouble);

or like this:

MyFun(nMyInt, szMyChar);

My compiler (VS 98) complains. Is there a way to do this?

Answer 1

You could overload the function instead.

// Definition
bool MyFun(int nMyInt, char* szMyChar, double& nMyReferencedDouble);

// Overload
bool MyFun(int nMyInt, char* szMyChar)
{
    double nMyReferencedDouble = 0.0;
    MyFun( nMyInt, szMyChar, nMyReferencedDouble );
}

This is how you get around the current limitations of no default values in C# and works equally well for semantic limitations in C++.