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Home/ Questions/Q 8406503
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T23:07:39+00:00 2026-06-09T23:07:39+00:00

Possible Duplicate: Django FileField with upload_to determined at runtime I am creating a web

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Possible Duplicate:
Django FileField with upload_to determined at runtime

I am creating a web application that allows user to store files online, like Dropbox. A user’s file is modeled by the model Item:

from django.db import models
from django.contrib.auth.models import User


class Item(models.Model):
    # Name of file
    name = models.CharField(max_length=200)

    # Site user who owns the file
    user = models.ForeignKey(User)

    # Path to file in database
    # Python complains here since "username" is an attribute of the User class, not
    # an attribute of ForeignKey.
    file = models.FileField(upload_to=(user.username + '/' + name))

Now if you look the upload_to argument to FileField, I want to specify where files are stored in my database. If I have a user “bill” with file “myfile” his file should go under the path “bill/myfile”.

To get this string I tried “user.username + ‘/’ + name” but python complains that user doesn’t have an attribute username because user isn’t a User object: it’s a ForeignKey that stores a User. So the question is, how do I get the user object from the ForeignKey within code?

Now regarding Django’s database API that won’t work because the object has to be saved to the database before I can use the API. This is not the case as I need the data during construction of my Item object.

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  1. Editorial Team
    Editorial Team
    2026-06-09T23:07:40+00:00Added an answer on June 9, 2026 at 11:07 pm

    With FileField you can put a [function on upload_to][1]

    https://docs.djangoproject.com/en/dev/ref/models/fields/#django.db.models.FileField.upload_to

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