Question

Possible Duplicate:
Does reading from stdin flush stdout?

C++ Standard guarantees that all data contained in the buffer will be printed before next call to std::cin. Like this:

#include <iostream>

void bar()
{
    int x;
    std::cout << "Enter an integer: "; /* 1 */
    std::cin >> x; /* 2 */
}

Because of this:

ISO/IEC 14882:2011

27.4.2 Narrow stream objects [narrow.stream.objects]

2 After the object cin is initialized, cin.tie() returns &cout. Its
state is otherwise the same as required for basic_ios::init
(27.5.5.2).

27.4.3 Wide stream objects [wide.stream.objects]

2 After the object wcin is initialized, wcin.tie() returns &wcout.
Its state is otherwise the same as required for
basic_ios::init (27.5.5.2).

But in C there are really no guarantees that everything contained in the stdout buffer will be printed before any attempt to stdin?

#include <stdio.h>

void bar()
{
    int x;
    printf("Enter an integer: "); /* 1 */
    scanf("%d", &x); /* 2 */
}

I know that stdout is line buffered but i don’t want to put ‘\n’ character in such situations. Is using fflush / fclose / etc is the only right way to get output right before input request in C?

Answer 1

No, there are no such guarantees.
Yes, you may use fflush() to ensure that stdout is flushed.

This question is closely related: Does reading from stdin flush stdout?