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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:15:19+00:00 2026-05-27T18:15:19+00:00

Possible Duplicate: Floating point arithmetic not producing exact results in Java Floating point inaccuracy

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Possible Duplicate:
Floating point arithmetic not producing exact results in Java
Floating point inaccuracy examples

In Java, given the following code:

    double amount = scan.nextDouble();

    tenBills = (int)amount / (int)10;
    amount = amount - (tenBills * 10);

    fiveBills = (int)amount / (int)5;
    amount = amount - (fiveBills * 5);

After the first calculation, given an input of say 16 amount will equal 6.66 . But after the second calculation amount will be 1.6600000000000001 . I don’t understand why subtracting an int from a double would cause such a result.

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:15:19+00:00Added an answer on May 27, 2026 at 6:15 pm

    Subtracting an int from a double does not change only the integer part of the double. It can also change the scale. In your particular case, the integer part before the subtraction (6) requires more bits to represent than the integer part after subtraction (1). This causes the entire representation of the number to allow for more fractional bits. Results can be (as you found out) a bit unexpected. (Pun intended)

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