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Home/ Questions/Q 8756067
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T13:59:00+00:00 2026-06-13T13:59:00+00:00

Possible Duplicate: Generating random number in a range with Java This feels pretty silly,

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Possible Duplicate:
Generating random number in a range with Java

This feels pretty silly, but I’m not sure how to create a random integer, giving it a specific range to allow. I was trying to make it generate random numbers between -1 and 1. I tried doing that, but the nextInt part doesn’t allow two parameters to be put within the parentheses. Am I supposed to be using something different?

import java.util.Random;

public class Testttterrrr {

    /**
     * @param args
     */
    public static void main(String[] args) {
        Random rng = new Random();
        for (int i=0;i < 10; i++)
        {
        int pepe = 0;
        pepe = rng.nextInt(1, 1-2);
        System.out.println(pepe);
        }
    }

}
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  1. Editorial Team
    Editorial Team
    2026-06-13T13:59:01+00:00Added an answer on June 13, 2026 at 1:59 pm

    You could do

    pepe = rng.nextInt(3) - 1;
    

    rng.nextInt(3) returns a random element in the set {0, 1, 2} – therefore subtracting 1 returns a random element in the set {-1, 0, 1}, as desired.


    Relevant documentation:

    • nextInt
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