Question

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generating random numbers from skewed normal distribution

i expect a long array containing integers
[3,7,7,7,7,1….]

but the overall distribution should be skewed and normal.

using random() generates a uniform distribution…..

Answer 1

If you are looking for just a few integers as your random numbers, then divide the range of random numbers accordingly.

For example, if your random function returns a number from zero to 1, and you want “3” to have a frequency of 10%, and “7” a frequency of 40%, you could say something like

uneven_rand()
{

r = rand();
if (r < 0.1) return 3; // covers range from 0 to 0.1
if (r < 0.5) return 7; // Covers range from 0.1 to 0.5
etc…

}