Question

Possible Duplicate:
Get the newest file based on timestamp

I primary want to select latest dump file from specific folder so i can store in variable and use it import using import script

I want to list specific files from a specific, I tried:

a= $(ls -ltr /home/oracle/testora/MAUL01*.dmp | awk '{print $9}' | tail -1)
echo $a

I want output as:

MAUL01.DP.09-27-2012_09_15.dmp

instead of:

/home/oracle/testora/MAUL01.DP.09-27-2012_09_15.dmp

Problems:
ls is not working for me inside sh (working fine from unix)
file name is shown with path (I trid using basename, but cannot make it work)

Answer 1

In bash, you can use the ${parameter##word} syntax to remove everything before the last /.

You can also use ls -tr1, then you won’t need awk.

This is shown below:

a=$(ls -tr1 /home/oracle/testora/MAUL01*.dmp | tail -1)
echo ${a##*/}