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Home/ Questions/Q 8496865
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T23:58:03+00:00 2026-06-10T23:58:03+00:00

Possible Duplicate: Grabbing the href attribute of an A element I’m trying to extract

  • 0

Possible Duplicate:
Grabbing the href attribute of an A element

I’m trying to extract some folders names from HTML page, The source code of the HTML looks like this ..

<li><a href="/"> Parent Directory</a></li>
<li><a href=".ftpquota"> .ftpquota</a></li>
<li><a href="Folder%201/"> Folder 1/</a></li>
<li><a href="Floder%202/"> Folder 2/</a></li>
<li><a href="Folder%20N/"> Folder N/</a></li>

What I created so far, I can extract some folders, but not extracted correctly.

Here is what I’ve done ..

<?php

    $url = "URL";
    $page_data = file_get_contents($url);
    $search_pattern = "<li><a href=";
    $position = 0;

    while($position = strpos($page_data,$search_pattern, $position+strlen($search_pattern)))
    {
        //$pos2 = strpos($page_data, "\"> ", $position);
        //echo $position . " - " . $pos2 . " = " . ($pos2-$position) . "<br />";
        $str = substr($page_data,$position+strlen($search_pattern)+1, $pos2-$position);
        echo "<pre>" . $position . " || " . $str . "\n</pre>";
    }

?>

Each folder contains some files that I will copy using copy() since I’m using Windows, so I don’t have wget.

What I’m doing wrong here??

This is my output:

156 || /"> Parent Directory
.ftpquota

Folder 1/

Folder 2/

Folder N/

But what I really need is:

Folder 1
Folder 2
Folder N

Cause later on, I’ll loop through the folders and copy the files.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T23:58:05+00:00Added an answer on June 10, 2026 at 11:58 pm

    Use DOMDocument and DOMXPath for HTML

    $string = '<li><a href="/"> Parent Directory</a></li>
    <li><a href=".ftpquota"> .ftpquota</a></li>
    <li><a href="Folder%201/"> Folder 1/</a></li>
    <li><a href="Floder%202/"> Folder 2/</a></li>
    <li><a href="Folder%20N/"> Folder N/</a></li>
    <li><a href="file.bin"> file.bin</a></li>';
    
    $html = new DOMDocument(); 
    $html->loadHTML($string);
    $xpath = new DOMXPath($html);
    $filtered = $xpath->query("//a/@href");
    
    foreach($filtered as $one){
        if(strlen($one->nodeValue) > 1) {
            echo urldecode($one->nodeValue)."\n";
        }
    }
    

    Codepad Example

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