Question

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How do i “echo” a “Resource id #6” from a MySql response in PHP?

I am looking for the result out of a query, but it keeps giving me resource id #3.

The following is my code.

$type = "SELECT `sellingid` FROM `ticket` WHERE `ticketid` = $_GET[ticketid]";
$typeResult = mysql_query($type);

print_r($typeResult);

What step am I missing here?

Answer 1

You need to fetch the result. All you’re doing is sending the query.

Be aware that if you are writing new code, you should use mysqli_ or PDO functions as your query is vulnerable to SQL injection and mysql_ functions are being deprecated. Hesitantly, below is a sample for mysql_fetch_assoc.

<?php

$sql = "SELECT `sellingid` FROM `ticket` WHERE `ticketid` = $_GET[ticketid]";

$result = mysql_query($sql);

if (mysql_num_rows($result) == 0) {
    echo "No rows found, nothing to print so am exiting";
    exit;
}

// While a row of data exists, put that row in $row as an associative array
// Note: If you're expecting just one row, no need to use a loop
// Note: If you put extract($row); inside the following loop, you'll
//       then create $userid, $fullname, and $userstatus
while ($row = mysql_fetch_assoc($result)) {
    echo $row[sellingid];
}

mysql_free_result($result);

?>

Reference