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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T01:51:10+00:00 2026-05-25T01:51:10+00:00

Possible Duplicate: How do I update if exists, insert if not (aka upsert or

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Possible Duplicate:
How do I update if exists, insert if not (aka upsert or merge) in MySQL?

I have a table with the columns user, category and score. I want to run an insert that, if this user/category combination already exists instead just updates the score. Both the user and the category column can have the same value many times but each specific user/category combination may only exist on one single row. How can I do this?

Many thanks

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  1. Editorial Team
    Editorial Team
    2026-05-25T01:51:11+00:00Added an answer on May 25, 2026 at 1:51 am

    For this example, let’s call your table scores:

    Make sure you have a unique index

    ALTER TABLE scores ADD UNIQUE INDEX user_category_ndx (user,category);
    

    Now run this to replace:

    INSERT INTO scores (user,category,score) VALUES ('username','mycat',127)
    ON DUPLICATE KEY UPDATE score = VALUES(score);
    

    If your updating the score means add up scores, then do this:

    INSERT INTO scores (user,category,score) VALUES ('username','mycat',127)
    ON DUPLICATE KEY UPDATE score = score + VALUES(score);
    

    Give it a try!

    UPDATE 2011-08-28 09:00 EDT

    If you want to keep just high scores and then add the unique index, here is what you must do:

    CREATE TABLE scores_new LIKE scores;
    ALTER TABLE scores_new ADD UNIQUE INDEX user_category_ndx (user,category);
    INSERT INTO scores_new (user,category,score)
    SELECT user,category,MAX(score) FROM scores GROUP BY user,category;
    ALTER TABLE scores RENAME scores_old;
    ALTER TABLE scores_new RENAME scores;
    #
    # Drop old table if no longer needed
    #
    DROP TABLE scores_old;
    

    UPDATE 2011-08-28 10:53 EDT

    Run this to keep maximum score:

    INSERT INTO scores (user,category,score) VALUES ('username','mycat',127)
    ON DUPLICATE KEY UPDATE score = GREATEST(VALUES(score),score);
    
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