Question

Possible Duplicate:
How do I zip the contents of a folder using python (version 2.5)?

Suppose I have a directory: /home/user/files/. This dir has a bunch of files:

/home/user/files/
  -- test.py
  -- config.py

I want to zip this directory using ZipFile in python. Do I need to loop through the directory and add these files recursively, or is it possible do pass the directory name and the ZipFile class automatically adds everything beneath it?

In the end, I would like to have:

/home/user/files.zip (and inside my zip, I dont need to have a /files folder inside the zip:)
  -- test.py
  -- config.py

Answer 1

You could use subprocess module:

import subprocess

PIPE = subprocess.PIPE
pd = subprocess.Popen(['/usr/bin/zip', '-r', 'files', 'files'],
                      stdout=PIPE, stderr=PIPE)
stdout, stderr = pd.communicate()

The code is not tested and pretends to works just on unix machines, i don’t know if windows has similar command line utilities.