Question

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How to associate a file extension to the current executable in C#

I dont know how exactly to call this issue.

I am looking for a solution such as: my .net application will be automatically opened when a filetyle defined for that application is open.

For example: the filetype of that application has an extension xyz: hellothere.xyz

Whenever, the user opens the file with an extension “xyz” then that .net application will be opened. How can I achieve this?

Thanks in advance.

Answer 1

A file association can be created manually in Windows Folder Options. This article describes how to do it programmatically, for example with a registry file:

• Create a string key for your file extension in HKEY_CLASSES_ROOT named .xyz.

• Set its value to the name of your file type, e.g., XyzDocument.

• Create a string key HKEY_CLASSES_ROOT\XyzDocument\open\shell\command.

• Set its value to "path\to\your\program" "%1" or similar, per your needs.

You can also do it from a batch script with ftype and assoc:

ftype XyzDocument="path\to\your\program" "%1"
assoc .xyz=XyzDocument