Question

Possible Duplicate:
How to call a function using pointer-to-member-function

Analyzer.h

class Analyzer
{
public :

    void viku();
    void Bibek();
    void vivek();
    void (Analyzer::*point)();

    Analyzer(){

    }
    ~Analyzer(){

    }

};

Analyzer.cpp

    using namespace std     
    #include"Analyzer.h"
    void Analyzer::viku(){
        cout<<"Hello viku";
    }
    void Analyzer::vivek(){
        point =&Analyzer::viku; 
        Bibek();   
    }
    void Analyzer::Bibek(){
           point();//Errror
        cout<<"Bibek";
    }

During compilation it shows the following error:

error C2064: term does not evaluate to a function taking 0 arguments.

Can anyone please tell me how to avoid this?

Answer 1

Pointers to member functions are different than normal function pointer. You need an instance to call them:

#include <iostream>

class A
{
public:
  int foo()
  {
      std::cout << "A::foo here, you can have 42" << std::endl;
      return 42;
  }
};

int main ()
{
  int (A::* point)() = &A::foo;
  A a;

  (a.*point)();
}

In your case, you’d need to do something like the following:

(this->*point)()