Question

Possible Duplicate:
how to call a PHP function from a form button

I’ve got a button like this:

<form method="post" id="submit" action="script/gen.php">
    <input type="button" onClick="getKey()" value="Generate key"/>

This calls a javascript in the same file that looks like this:

<script type="text/javascript">
        function getKey() {
            if (window.XMLHttpRequest) {
                xmlhttp=new XMLHttpRequest();

        }
        else {
            xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
        }

        xmlhttp.onreadystatechange=function() {
        if (xmlhttp.readyState==4 && xmlhttp.status==200) {
            document.getElementById("innhold").innerHTML=xmlhttp.responseText;
        }
    }
        xmlhttp.open("GET","script/gen.php?returnKey",true);
        xmlhttp.send();
    }
</script>

I know that this javascript is beeing called, by adding an alert() several places inside the script. The problem occurs when I try to do an isset in my php code:

else if(isset($_GET['returnKey'])) {
returnKey();
}

This function is never beeing called, even if I add a echo before I do the function call returnKey()

Can anyone see where the problem is?

EDIT

This is what the console has to tell me, from chrome:

XMLHttpRequest cannot load file:///C:/wamp/www/Webpanel/script/gen.php?returnKey. Cross    origin requests are only supported for HTTP.
Uncaught Error: NETWORK_ERR: XMLHttpRequest Exception 101 index.html:37
getKey index.html:3

EDIT 2

Holy moses, I figured it out. Had to type in localhost/Webpanel in my browser. Its been a long day, so I not quite clear..

Answer 1

Solved to problem:

I tried to open my index.htmllocally, this is the right way to do it, ofc. Type in localhost in the browser. You have to run WAMP.