Question

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How to find the 'sizeof' (a pointer pointing to an array)?

I red this but it didn’t help me much.

int* sum;
int size = 10;
sum = calloc(10, sizeof(int));

printf("Total length: %d", sizeof(sum)/sizeof(*sum))

The code returns 1 as expected.

I know that it would be easier to user the size variable.

My question is that is there a way of finding out this array correct size using sizeof?

Answer 1

Other than keeping track of the size yourself (eg. the size variable in your example), there’s no portable/standard way of getting the size of a dynamically allocated block of memory.