Question

Possible Duplicate:
How to find the sizeof(a pointer pointing to an array)

sample code written in c

#include<stdio.h>

int main()
{
    char a[]="Visual C++";
    char b[] = "Visual\C++";
    printf("%d, %d\n", sizeof(a), sizeof(b));
    printf("%d, %d", sizeof(*a), sizeof(*b));
    return 0;
}

OUTPUT

11,10

1,1

1.) Why sizeof(a) shows 11, although, it has only 10 characters.

2.) Why sizeof(a) and sizeof(b) showing different output, although, they have same number of characters.

Answer 1

Because there is a null (\0) at the end of the string and \C is interpreted as a single character.

If you want the backslash to show in a C string you must escape it using another backslash.

char b[] = "Visual\C++";  \\ 10 characters including the null terminator
char b[] = "Visual\\C++"; \\ 11 characters including the null terminator