Question

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How to increment date with 1 (day/year) in PHP?

Im not really sure where to begin with this but im trying to make a year start at 1928 and stop at 1948 and for every year the years increment by one so since its 2012 the date ranges are 1928 – 1948 and for 2013 it would be 1929 – 1949 and 2014 would be 1930 – 1950 and so on…

right now i just have a basic loop for when to start and stop the years but its not too dynamic, like i said im pretty much at a blank on where to begin other then date(‘Y’)+1.

for($i=1928;$i<=date('Y');$i++)
{
    echo '<option value='.$i.'>'.$i.'</option>';
    if($i == '1948'){break;}
}

Answer 1

So you want it to go between current year minus 84 and the current year minus 64? Use this code:

$firstYear = (int)date('Y') - 84;
$lastYear = $firstYear + 20;
for($i=$firstYear;$i<=$lastYear;$i++)
{
    echo '<option value='.$i.'>'.$i.'</option>';
}

Edit: updated for performance. Current year is determined before the loop (per Pitchinnate’s comment).