Question

Possible Duplicate:
how to “return an object” in C++

I am wondering if there is a difference between the three following approaches:

void FillVector_1(vector<int>& v) {
    v.push_back(1); // lots of push_backs!
}

vector<int> FillVector_2() {
    vector<int> v;
    v.push_back(1); // lots of push_backs!
    return v;
}

vector<int> FillVector_3() {
    int tab[SZ] = { 1, 2, 3, /*...*/ };
    return vector<int>(tab, tab + SZ);
}

Answer 1

The biggest difference is that the first way appends to existing contents, whereas the other two fill an empty vector. 🙂

I think the keyword you are looking for is return value optimization, which should be rather common (with G++ you’ll have to turn it off specifically to prevent it from being applied). That is, if the usage is like:

vector<int> vec = fill_vector();

then there might quite easily be no copies made (and the function is just easier to use).

If you are working with an existing vector

vector<int> vec;
while (something)
{
    vec = fill_vector();
    //do things
}

then using an out parameter would avoid creation of vectors in a loop and copying data around.