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Possible Duplicate:
In a C function declaration, what does “…” as the last parameter do?
What does this mean ,...); it is written at the end of a function in a code i am debuging.
like this void abc( int a, int b, ...);
It means the function can take any number of extra arguments. For example, consider printf; the first argument is the format string, and then there can be any number of arguments after that for all of the modifiers. This would be represented by using … after the first argument when defining the function.