Question

Possible Duplicate:
In Python, fastest way to build a list of files in a directory with a certain extension

I currently am using os.walk to recursively scan through a directory identifying .MOV files

def fileList():
    matches = []
    for root, dirnames, filenames in os.walk(source):
        for filename in fnmatch.filter(filenames, '*.mov'):
            matches.append(os.path.join(root, filename))
    return matches

How can I extend this to identify multiple files, e.g., .mov, .MOV, .avi, .mpg?

Thanks.

Answer 1

Try something like this:

def fileList(source):
    matches = []
    for root, dirnames, filenames in os.walk(source):
        for filename in filenames:
            if filename.endswith(('.mov', '.MOV', '.avi', '.mpg')):
                matches.append(os.path.join(root, filename))
    return matches