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Home/ Questions/Q 7971121
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T07:33:59+00:00 2026-06-04T07:33:59+00:00

Possible Duplicate: instanceof – incompatible conditional operand types I am testing JAVA instance of

  • 0

Possible Duplicate:
instanceof – incompatible conditional operand types

I am testing JAVA “instance of” operator for brush up my mind. I see that the keyword is used to check if a reference is instance of a class or not.

But we use a reference to compare with a class that is not having any IS-A relationship with the class then it gives compile time error.

See the following code :

package instanceofdemo;
public class Sample_1 {

    public static void main(String a[]){
        A iface = new Subclass();

        ///HERE INTERFACE OBJECT IS DOWNCASTED TO SUBCLASS
        if(iface instanceof  SuperClass){
            System.out.println("iface instanceof  SuperClass");
        }

        ///HERE INTERFACE OBJECT IS DOWNCASTED TO SUBCLASS
        if(iface instanceof  Subclass){
            System.out.println("iface instanceof  Subclass");
        }

        if(iface instanceof  A){
            System.out.println("iface instanceof  A");
        }


        Subclass sub = new Subclass();

        //SO INSTANCE OF ONLY WORKS WITH IS-A RELATION SHIP IN BI-DIRECTIONAL WAY
        //IT WILL GIVE COMPILE TIME ERROR, IF YOU TRY TO USE INSTANCE-OF WITH NON-RELATED CLASS
        if(sub instanceof  Independent){

        }

    }

}

interface  A{

}


class SuperClass implements A {

}



class Subclass extends  SuperClass{

}

class Independent{

}

In above code : when it gives compilation error at if(iface instance of Independent) line bcoz iface is not in “IS-A” relationship with Independent.

Then what is the exact use of insatance of keyword ?
If its used only with “IS-A” relationship then…where are the changes for the if condition to be false ??

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T07:34:00+00:00Added an answer on June 4, 2026 at 7:34 am

    It’s a feature, not a bug. Compiler prevents you from you using instanceof operator in situations where it is basically impossible that it will ever be met, e.g.:

    String s = "abc";
    if(s instanceof Integer) {
    }
    

    s instanceof Integer can never be true. However checking is performed at compile time, so this compiles:

    Object s = "abc";
    if(s instanceof Integer) {
    }
    
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