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Home/ Questions/Q 6589667
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T17:12:14+00:00 2026-05-25T17:12:14+00:00

Possible Duplicate: Is there a way to initialize an array with non-constant variables? (C++)

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Possible Duplicate:
Is there a way to initialize an array with non-constant variables? (C++)

I have the following code:

vector<vector<vec2>> vinciP;
    int myLines = -1;
    myLines = drawPolyLineFile("vinci.dat", vinciP);
    if (myLines > -1)
    {
        cout << "\n\nSUCCESS";
        vec2 vPoints[myLines];
        for (int i = 0; i < NumPoints; ++i)
        {
            vPoints[i] = vinciP[0][i];
        }
    }

I’m getting an error on the line ‘vec2 vPoints[myLines];’ that says expressions must have a constant value. I don’t understand why I’m getting this error, any help?

Is it because myLines could be negative? idk.

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  1. Editorial Team
    Editorial Team
    2026-05-25T17:12:15+00:00Added an answer on May 25, 2026 at 5:12 pm
    vec2 vPoints[myLines];
    

    Since myLines is not a const expression ((which means, it is not known at compile-time), so the above code declares a variable length array which is not allowed in C++. Only C99 has this feature. Your compiler might have this as an extension (but that is not Standard C++).

    The solution to such commom problem is : use std::vector<T> as:

    std::vector<vec2> vPoints(myLines);
    

    It should work now.

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