Question

Possible Duplicate:
Is there memset() that accepts integers larger than char?

As it can be seen in memset’s declaration:

void * memset ( void * ptr, int value, size_t num );

Is there any way to use this memset function (or another function included in STL library) so that you can set memory to a long long type value?

I use this to initialize an array of long longs with a large value.

I have to say that I’ve “solved” this problem by simply iterating through each value of the array and setting it to the desired value.

Answer 1

memset only uses one byte of the value passed in and does bytewise initialization. If you want to initialize a long long array with a particular value, just use std::fill or std::fill_n and let your library and compiler optimize it as they can (partial loop unrolling etc).

Another canonical C++ way is to just use vector and let its constructor do the work for you:

std::vector<long long> foo(length_of_array, 12345678901234LL);