Question

Possible Duplicate:
Java code to execute a .sh file

I write the code in a .sh file with one parameter in /root/new_scripts/setpermission.sh and run it: setpermission.sh contains:

chmod 777 $1

It executed successfully from linux console by typing /root/new_scripts/setpermission.sh location . But when i tried to run it using java code using:
Java full code:

String fileLocation = BASE_DIR + domain + SUB_DIR_CAKE + fileName;
    File newFile = new File(fileLocation);
    System.out.println("Permission file location: " + fileLocation);
    if(newFile.exists()) {
        String command;
        String[] commandArray;
        command = "/root/new_scripts/setpermission.sh";
        File commandFile = new File(command);
        if(commandFile.exists()) {
            System.out.println("\n\n\n\n\nFILE EXISTS");
        } else {
            System.out.println("\n\n\n\n\nFILE NOT EXISTS");
        }
        commandArray = new String[]{"/bin/sh", command, newFile.toString()};
        try {
            Process p = Runtime.getRuntime().exec(commandArray);
            return "HERE OK";
        } catch (Exception e) {
            e.printStackTrace();
            return e.getMessage();
        }
    } else {
        return "file not exists";
    }

and it returns HERE OK

Answer 1

try this:

            String command;
            String[] commandArray;


            command = "./new_scripts/setpermission.sh";
            commandArray = new String[]{"/bin/sh", command, fileLocation, permission};
          try {

              Process p = Runtime.getRuntime().exec(commandArray);

         } catch (Exception e) {

            // TODO Auto-generated catch block
            e.printStackTrace();
        }