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Home/ Questions/Q 7541405
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T07:52:59+00:00 2026-05-30T07:52:59+00:00

Possible Duplicate: Javascript infamous Loop problem? With the for loop, it does nothing. Without

  • 0

Possible Duplicate:
Javascript infamous Loop problem?

With the for loop, it does nothing. Without the for loop, it works perfect.

Without the for loop:

var refreshId = setInterval(function(){
  $("#k1").fadeTo(1000,0.01,callfunc).fadeTo(1000,1);
}, 5000);
var refreshId = setInterval(function(){
  $("#k2").fadeTo(1000,0.01,callfunc).fadeTo(1000,1);
}, 5000);

and so on…

With the for loop:

for(var i=1;i<7;i++){
  var refreshId = setInterval(function(){
    $("#k"+i).fadeTo(1000,0.01,callfunc).fadeTo(1000,1);
  }, 5000);
}

What am I doing wrong here?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T07:53:00+00:00Added an answer on May 30, 2026 at 7:53 am

    As @pimvdb pointed out you have closure (setTimeout creates one) inside loop, it won’t work, you should have something like:

    for(var i = 1; i < 7; i++) {
        (function(e) {
            var refreshId = setTimeout(function() {
                $("#k"+e).fadeTo(1000,0.01,callfunc).fadeTo(1000,1);
            }, 5000);
        })(i);
    }
    

    You may also want to take a look at this question for more information.

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