Question

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JavaScript RegExp Three Parts

I need a help with regular expressions in JavaScript (Sorry, I’m still trying to learn it.).

I have this strings:

all (any) -del
all -del (any)
all (any)
all -del
all

PS: all, any and del can assume any value, including spaces.

And I need to separate each string:

var1 = all
var2 = any (or null)
var3 = del (or null)

Can you help me with this? Thanks!

Answer 1

How about:

/^(.*?)\s?(\(.*?\)|)\s?(-.*?|)$/

application to your examples:

'all (any) -del'.match(/^(.*?)\s?(\(.*?\)|)\s?(-.*?|)$/)
["all (any) -del", "all", "(any)", "-del"]

'all (any)'.match(/^(.*?)\s?(\(.*?\)|)\s?(-.*?|)$/)
["all (any)", "all", "(any)", ""]

'all -del'.match(/^(.*?)\s?(\(.*?\)|)\s?(-.*?|)$/)
["all -del", "all", "", "-del"]

'all'.match(/^(.*?)\s?(\(.*?\)|)\s?(-.*?|)$/)
["all", "all", "", ""]

To process new requirement, a little bit complex:

'all (any) -del'.match(/^(.*?)(?:\s?(\([^-]*\)|)\s?(-[^()]*|)|\s?(-[^()]*|)\s?(\([^-]*\)|))$/)
["all (any) -del", "all", "(any)", "-del", undefined, undefined]
'all -del (any)'.match(/^(.*?)(?:\s?(\([^-]*\)|)\s?(-[^()]*|)|\s?(-[^()]*|)\s?(\([^-]*\)|))$/)
["all -del (any)", "all", undefined, undefined, "-del ", "(any)"]