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Home/ Questions/Q 8659215
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T15:57:36+00:00 2026-06-12T15:57:36+00:00

Possible Duplicate: JQuery .each() backwards I am using this code to show each div

  • 0

Possible Duplicate:
JQuery .each() backwards

I am using this code to show each div -> this with a delay an an animation:

$.fn.slideDelay = function(){
    var delay = 0;
    return this.each(function(){
        $(this).delay(delay).animate({
            opacity: 1,
            top: 0
        }, 2000);
        delay += 1000;
    });
};

Works well so far… the only Problem i got is that i need to start with the last index not the first one. Which means the last div gets animated first then the beforelast and so on until the first one.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T15:57:37+00:00Added an answer on June 12, 2026 at 3:57 pm

    Theoretically the following should work:

    $.fn.slideDelay = function() {
        var len = this.length,
            delay = (len - 1) * 1000;
    
        return this.each(function() {
            $(this).delay(delay).animate({
                opacity: 1,
                top: 0
            }, 2000);
            delay -= 1000;
        });
    };
    

    DEMO: http://jsfiddle.net/q4cGP/

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